(x^2+3)+(2x^2-4)=

Solution for (x^2+3)+(2x^2-4)= equation:

Simplifying
(x2 + 3) + (2x2 + -4) = 0

Reorder the terms:
(3 + x2) + (2x2 + -4) = 0

Remove parenthesis around (3 + x2)
3 + x2 + (2x2 + -4) = 0

Reorder the terms:
3 + x2 + (-4 + 2x2) = 0

Remove parenthesis around (-4 + 2x2)
3 + x2 + -4 + 2x2 = 0

Reorder the terms:
3 + -4 + x2 + 2x2 = 0

Combine like terms: 3 + -4 = -1
-1 + x2 + 2x2 = 0

Combine like terms: x2 + 2x2 = 3x2
-1 + 3x2 = 0

Solving
-1 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 3x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 3x2 = 0 + 1
3x2 = 0 + 1

Combine like terms: 0 + 1 = 1
3x2 = 1

Divide each side by '3'.
x2 = 0.3333333333

Simplifying
x2 = 0.3333333333

Take the square root of each side:
x = {-0.577350269, 0.577350269}